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author | Qu Wenruo <quwenruo@cn.fujitsu.com> | 2017-05-18 10:51:08 +0800 |
---|---|---|
committer | David Sterba <dsterba@suse.com> | 2017-07-03 13:35:11 +0200 |
commit | 8690c887d1dcad384d44ca21bf950a4ec2fbffdb (patch) | |
tree | bf736b51824e4e834c4d0e8ea79169bf40849d04 /print-tree.c | |
parent | 060c7b3a1a40d2e9cacbdb37a02791bacae32491 (diff) |
btrfs-progs: Refactor read_tree_block to get rid of btrfs_root
The only reasom read_tree_block() needs a btrfs_root parameter is to get
its node/sector size.
And long ago, I have already introduced a compactible interface,
read_tree_block_fs_info() to pass btrfs_fs_info instead of btrfs_root.
Since we have cleaned up all root->sector/node/stripesize users, we
should be OK to refactor read_tree_block() function.
Signed-off-by: Qu Wenruo <quwenruo@cn.fujitsu.com>
Diffstat (limited to 'print-tree.c')
-rw-r--r-- | print-tree.c | 3 |
1 files changed, 2 insertions, 1 deletions
diff --git a/print-tree.c b/print-tree.c index 1b15640b..07366e98 100644 --- a/print-tree.c +++ b/print-tree.c @@ -1314,7 +1314,8 @@ void btrfs_print_tree(struct btrfs_root *root, struct extent_buffer *eb, int fol return; for (i = 0; i < nr; i++) { - next = read_tree_block(root, btrfs_node_blockptr(eb, i), size, + next = read_tree_block(root->fs_info, + btrfs_node_blockptr(eb, i), size, btrfs_node_ptr_generation(eb, i)); if (!extent_buffer_uptodate(next)) { fprintf(stderr, "failed to read %llu in tree %llu\n", |