summaryrefslogtreecommitdiff
path: root/examples/xsh.c
blob: 13971a2db35a0b543dd27e1224935b824e0c8757 (plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
/*
 * $Id$
 */

/* Andrew Morgan (morgan@kernel.org) -- an example application
 * that invokes a shell, based on blank.c */

#include <stdio.h>
#include <stdlib.h>

#include <security/pam_appl.h>
#include <security/pam_misc.h>

/* ------ some local (static) functions ------- */

static void bail_out(pam_handle_t *pamh,int really, int code, const char *fn)
{
     fprintf(stderr,"==> called %s()\n  got: `%s'\n", fn,
	     pam_strerror(pamh,code));
     if (really && code)
	  exit (1);
}

/* ------ some static data objects ------- */

static struct pam_conv conv = {
     misc_conv,
     NULL
};

/* ------- the application itself -------- */

int main(int argc, char **argv)
{
     pam_handle_t *pamh=NULL;
     char *username=NULL;
     int retcode;

     /* did the user call with a username as an argument ? */

     if (argc > 2) {
	  fprintf(stderr,"usage: %s [username]\n",argv[0]);
     } else if (argc == 2) {
	  username = argv[1];
     } 

     /* initialize the Linux-PAM library */
     retcode = pam_start("xsh", username, &conv, &pamh);
     bail_out(pamh,1,retcode,"pam_start");

     /* to avoid using goto we abuse a loop here */
     for (;;) {
	  /* authenticate the user --- `0' here, could have been PAM_SILENT
	   *	| PAM_DISALLOW_NULL_AUTHTOK */

	  retcode = pam_authenticate(pamh, 0);
	  bail_out(pamh,0,retcode,"pam_authenticate");

	  /* has the user proved themself valid? */
	  if (retcode != PAM_SUCCESS) {
	       fprintf(stderr,"%s: invalid request\n",argv[0]);
	       break;
	  }

	  /* the user is valid, but should they have access at this
	     time? */

	  retcode = pam_acct_mgmt(pamh, 0); /* `0' could be as above */
	  bail_out(pamh,0,retcode,"pam_acct_mgmt");

	  if (retcode == PAM_NEW_AUTHTOK_REQD) {
	       fprintf(stderr,"Application must request new password...\n");
	       retcode = pam_chauthtok(pamh,PAM_CHANGE_EXPIRED_AUTHTOK);
	       bail_out(pamh,0,retcode,"pam_chauthtok");
	  }

	  if (retcode != PAM_SUCCESS) {
	       fprintf(stderr,"%s: invalid request\n",argv[0]);
	       break;
	  }

	  /* `0' could be as above */
	  retcode = pam_setcred(pamh, PAM_ESTABLISH_CRED);
	  bail_out(pamh,0,retcode,"pam_setcred");

	  if (retcode != PAM_SUCCESS) {
	       fprintf(stderr,"%s: problem setting user credentials\n"
		       ,argv[0]);
	       break;
	  }

	  /* open a session for the user --- `0' could be PAM_SILENT */
	  retcode = pam_open_session(pamh,0);
	  bail_out(pamh,0,retcode,"pam_open_session");
	  if (retcode != PAM_SUCCESS) {
	       fprintf(stderr,"%s: problem opening a session\n",argv[0]);
	       break;
	  }

	  fprintf(stderr,"The user has been authenticated and `logged in'\n");

	  /* this is always a really bad thing for security! */
	  system("/bin/sh");

	  /* close a session for the user --- `0' could be PAM_SILENT
	   * it is possible that this pam_close_call is in another program..
	   */

	  retcode = pam_close_session(pamh,0);
	  bail_out(pamh,0,retcode,"pam_close_session");
	  if (retcode != PAM_SUCCESS) {
	       fprintf(stderr,"%s: problem closing a session\n",argv[0]);
	       break;
	  }
	  
	  break;                      /* don't go on for ever! */
     }

     /* close the Linux-PAM library */
     retcode = pam_end(pamh, PAM_SUCCESS);
     pamh = NULL;
     bail_out(pamh,1,retcode,"pam_end");

     exit(0);
}