Lua filters: stop exporting pushPandocModule

The function `pushPandocModule` was exported by Text.Pandoc.Lua to
enable simpler testing. The introduction of `runPandocLua` renders
direct use of this function obsolete. (API change)

1 files changed, 0 insertions, 6 deletions

diff --git a/src/Text/Pandoc/Lua.hs b/src/Text/Pandoc/Lua.hs
index 02e1b0424..d02963418 100644
--- a/src/Text/Pandoc/Lua.hs
+++ b/src/Text/Pandoc/Lua.hs
@@ -29,7 +29,6 @@ module Text.Pandoc.Lua
   ( LuaException (..)
   , runLuaFilter
   , runPandocLua
-  , pushPandocModule
   ) where
 
 import Control.Monad ((>=>))
@@ -39,7 +38,6 @@ import Text.Pandoc.Class (PandocIO)
 import Text.Pandoc.Definition (Pandoc)
 import Text.Pandoc.Lua.Filter (LuaFilter, walkMWithLuaFilter)
 import Text.Pandoc.Lua.Init (runPandocLua)
-import Text.Pandoc.Lua.Module.Pandoc (pushModule) -- TODO: remove
 import Text.Pandoc.Lua.Util (popValue)
 import qualified Foreign.Lua as Lua
 
@@ -77,7 +75,3 @@ runLuaFilter' filterPath format pd = do
 
 runAll :: [LuaFilter] -> Pandoc -> Lua Pandoc
 runAll = foldr ((>=>) . walkMWithLuaFilter) return
-
--- | DEPRECATED: Push the pandoc module to the Lua Stack.
-pushPandocModule :: Maybe FilePath -> Lua Lua.NumResults
-pushPandocModule = pushModule